Tba^2 Jokes

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    Theorem: All numbers are equal.Proof: Choose arbitrary a and b, and let t = a + b. Thena + b = t(a + b)(a - b) = t(a - b)a^2 - b^2 = ta - tba^2 - ta = b^2 - tba^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4(a - t/2)^2 = (b - t/2)^2a - t/2 = b - t/2a = bSo all numbers are the same, and math is pointless.

    Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Thena + b = t(a + b)(a - b) = t(a - b)a^2 - b^2 = ta - tba^2 - ta = b^2 - tba^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4(a - t/2)^2 = (b - t/2)^2a - t/2 = b - t/2a = bSo all numbers are the same, and math is pointless.

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    Theorem by Anonym